All x satisfying the inequality

$\left(\cot ^{-1} x\right)^{2}-7\left(\cot ^{-1} x\right)+10>0$

$\left(\cot ^{-1} x-5\right)\left(\cot ^{-1}-2\right)>0$

$\cot ^{-1} x \in(-\infty, 2) \cup(5, \infty)$ ...(1)

But $\cot ^{-1} x$ lies in $(0, \pi)$

Now, from equation (1)

$\cot ^{-1} x \in(0,2)$

Now, it is clear from the graph

$x \in(\cot 2, \infty)$