According to the valence bond theory the hybridization

Question:

According to the valence bond theory the hybridization of central metal atom is $\mathrm{dsp}^{2}$ for which one of the following compounds?

  1. $\mathrm{NiCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}$

  2. $\mathrm{K}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]$

  3. $\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$

  4. $\mathrm{Na}_{2}\left[\mathrm{NiCl}_{4}\right]$

Correct Option: , 2

Solution:

1) $\mathrm{NiCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}$

$\mathrm{Ni}^{+2} \rightarrow[\mathrm{Ar}]_{18} 3 \mathrm{~d}^{8} 4 \mathrm{~s}^{0}$

C.N. $=6$ octahedral

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