Question:
According to the following diagram, $\mathrm{A}$ reduces $\mathrm{BO}_{2}$ when the temperature is:
Correct Option: , 2
Solution:
$\mathrm{A}+\mathrm{BO}_{2} \longrightarrow \mathrm{B}+\mathrm{AO}_{2}$
$\Delta \mathrm{G}=-\mathrm{ve}$
when the temperature is above $1400^{\circ} \mathrm{C}$, A reduces $\mathrm{BO}_{2}$.