Question:
$\mathrm{ABCD}$ is a trapezium such that $\mathrm{AB}$ and $C D$ are parallel and $\mathrm{BC} \perp \mathrm{CD}$. If $\angle \mathrm{ADB}=\theta, \mathrm{BC}$ $=\mathrm{p}$ and $\mathrm{CD}=\mathrm{q}$, then $\mathrm{AB}$ is equal to
Correct Option: 1
Solution: