A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel.
For hemispherical part, radius (r) $=\frac{\mathbf{1 4}}{\mathbf{2}}=7 \mathrm{~cm}$
$\therefore \quad$ Curved surface area $=2 \pi \mathrm{r}^{2}$
$=2 \times \frac{22}{7} \times 7 \times 7 \mathrm{~cm}^{2}=308 \mathrm{~cm}^{2}$
Total height of vessel $=13 \mathrm{~cm}$
$\therefore$ Height of cylinder $=(13-7) \mathrm{cm}=6 \mathrm{~cm}$ and radius $(\mathrm{r})=7 \mathrm{~cm}$
$\therefore \quad$ Curved surface area of cylinder $=2 \pi \mathrm{rh}$
$=2 \times \frac{\mathbf{2 2}}{\mathbf{7}} \times 7 \times 6 \mathrm{~cm}^{2}=264 \mathrm{~cm}^{2}$
$\therefore \quad$ Inner surface area of vessel $=$ Curved surface area of hemispherical part $+$ Curved surface area of cylinder
$=(308+264) \mathrm{cm}^{2}=572 \mathrm{~cm}^{2}$