A value of $\alpha$ such that
$\int_{\alpha}^{\alpha+1} \frac{d x}{(x+\alpha)(x+\alpha+1)}=\log _{e}\left(\frac{9}{8}\right)$ is :
$\frac{1}{2}$
2
$-\frac{1}{2}$
$-2$
Correct Option: , 4
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