A tree breaks due to the storm and the broken part bends so that the top

Let AB be the tree of height h. And the top of tree makes an angle 30° with ground. The distance between foot of tree to the point where the top touches the ground is m. Let BC = 10. And.

Here we have to find height of tree.

Here we have the corresponding figure

So we use trigonometric ratios.

In a triangle,

$\Rightarrow \quad \tan C=\frac{A B}{B C}$

$\Rightarrow \quad \tan 30^{\circ}=\frac{A B}{B C}$

$\Rightarrow \quad \frac{1}{\sqrt{3}}=\frac{h}{10}$

$\Rightarrow \quad h=\frac{10}{\sqrt{3}}$

Now in triangle ABC we have

$\sin 30^{\circ}=\frac{h}{A C}$

$\Rightarrow \frac{1}{2}=\frac{10}{\sqrt{3} A C}$

$\Rightarrow A C=\frac{20}{\sqrt{3}}$

So the length of the tree is

$=A B+A C$

$=h+A C$

$=\frac{10}{\sqrt{3}}+\frac{20}{\sqrt{3}}$

$=10 \sqrt{3}$

$=1.73$

Hence the height of tree is $17.3 \mathrm{~m}$.