Question.
A train starting from a railway station and moving with uniform acceleration attains a speed of 40 kmh–1 in 10 minutes. Find its acceleration.
A train starting from a railway station and moving with uniform acceleration attains a speed of 40 kmh–1 in 10 minutes. Find its acceleration.
Solution:
Given $t=10 \mathrm{~min}=10 \times 60=600 \mathrm{~s}$
Initial speed of train, $\mathrm{u}=0 \mathrm{~ms}^{-1}$
Final speed of train
$\mathrm{v}=40 \mathrm{~km} \mathrm{~h}^{-1}=40 \times \frac{5}{18}=11.1 \mathrm{~ms}^{-1}$
Now acceleration is given by the relation
$\mathrm{a}=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}=\frac{11.1-0}{600}=0.0185 \mathrm{~ms}^{-2}$
Given $t=10 \mathrm{~min}=10 \times 60=600 \mathrm{~s}$
Initial speed of train, $\mathrm{u}=0 \mathrm{~ms}^{-1}$
Final speed of train
$\mathrm{v}=40 \mathrm{~km} \mathrm{~h}^{-1}=40 \times \frac{5}{18}=11.1 \mathrm{~ms}^{-1}$
Now acceleration is given by the relation
$\mathrm{a}=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}=\frac{11.1-0}{600}=0.0185 \mathrm{~ms}^{-2}$