Question:
A tetrahedron has vertices $\mathrm{P}(1,2,1)$, $\mathrm{Q}(2,1,3), \mathrm{R}(-1,1,2)$ and $\mathrm{O}(0,0,0)$. The angle between the faces OPQ and PQR is :
Correct Option: 1
Solution:
$\overrightarrow{\mathrm{OP}} \times \overrightarrow{\mathrm{OQ}}=(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}) \times(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+3 \hat{\mathrm{k}})$
$5 \hat{\mathrm{i}}-\hat{\mathrm{j}}-3 \hat{\mathrm{k}}$
$\overrightarrow{P Q} \times \overrightarrow{P R}=(\hat{i}-\hat{j}+2 \hat{k}) \times(-2 \hat{i}-\hat{j}+\hat{k})$
$\hat{\mathrm{i}}-5 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}$
$\cos \theta=\frac{5+5+9}{(\sqrt{25+9+1})^{2}}=\frac{19}{35}$