Question:
A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?
Solution:
Length of the tank $=8 \mathrm{~m}$
Breadth $=6 \mathrm{~m}$
Height $=2 \mathrm{~m}$
$\therefore$ Its volume $=$ length $\times$ breadth $\times$ height $=(8 \times 6 \times 2) \mathrm{m}^{3}=96 \mathrm{~m}^{3}$
We know that $1 \mathrm{~m}^{3}=1000 \mathrm{~L}$
Now, $96 \mathrm{~m}^{3}=96 \times 1000 \mathrm{~L}=96000 \mathrm{~L}$
$\therefore$ The tank can store $96000 \mathrm{~L}$ of water.