A sum of ₹2800 is to be used to award four prizes. If each prize after the first is ₹200 less than the preceding prize, find the value of each of the prizes.
Let the amount of the first prize be ₹a.
Since each prize after the first is ₹200 less than the preceding prize, so the amounts of the four prizes are in AP.
Amount of the second prize = ₹(a − 200)
Amount of the third prize = ₹(a − 2 × 200) = ₹(a − 400)
Amount of the fourth prize = ₹(a − 3 × 200) = ₹(a − 600)
Now,
Total sum of the four prizes = ₹2,800
∴ ₹a + ₹(a − 200) + ₹(a − 400) + ₹(a − 600) = ₹2,800
⇒ 4a − 1200 = 2800
⇒ 4a = 2800 + 1200 = 4000
⇒ a = 1000
∴ Amount of the first prize = ₹1,000
Amount of the second prize = ₹(1000 − 200) = ₹800
Amount of the third prize = ₹(1000 − 400) = ₹600
Amount of the fourth prize = ₹( 1000 − 600) = ₹400
Hence, the value of each of the prizes is ₹1,000, ₹800, ₹600 and ₹400.