A sum amounts to Rs 23762 in 2 years at 9% per annum, compounded annually.

Amount $(A)=$ Rs 23762

Rate of interest $(\mathrm{R})=9 \%$

Time $(n)=2$ years

Now, $A=P \times\left(1+\frac{R}{100}\right)^{n}$

$\Rightarrow$ Rs $23762=P \times\left(1+\frac{9}{100}\right)^{2}$

$\Rightarrow$ Rs $23762=P \times\left(\frac{109}{100}\right) \times\left(\frac{109}{100}\right)$

$\Rightarrow P=$ Rs $\frac{23762 \times 100 \times 100}{109 \times 109}$

$\Rightarrow P=$ Rs 20000

$\therefore$ The principal amount is Rs 20000 .