A steel wire having a radius of 2.0 mm, carrying a load of 4 kg,

Question:

A steel wire having a radius of $2.0 \mathrm{~mm}$, carrying a load of $4 \mathrm{~kg}$, is hanging from a ceiling. Given that $\mathrm{g}=3.1 \pi \mathrm{ms}^{-2}$, what will be the tensile stress that would be developed in the wire?

  1. $6.2 \times 10^{6} \mathrm{Nm}^{-2}$

  2. $5.2 \times 10^{6} \mathrm{Nm}^{-2}$

  3. $3.1 \times 10^{6} \mathrm{Nm}^{-2}$

  4. $4.8 \times 10^{6} \mathrm{Nm}^{-2}$


Correct Option: , 3

Solution:

(3) Given,

Radius of wire, $r=2 \mathrm{~mm}$

Mass of the load $m=4 \mathrm{~kg}$

Stress $=\frac{F}{A}=\frac{m g}{\pi(r)^{2}}$

$=\frac{4 \times 3.1 \pi}{\pi \times\left(2 \times 10^{-3}\right)^{2}}=3.1 \times 10^{6} \mathrm{~N} / \mathrm{m}^{2}$

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