A square water tank has its side equal to 40 m. There are four semi-circular grassy plots all round it. Find the cost of turfing the plot at Rs. 1.25 per square metre (Take π = 3.14).
It is given that the side of square $a=40 \mathrm{~m}$ -
Since four semicircular grassy plots rounds a square water tank. Then, diameter of semicircular plot is $2 r=a$.
So, the radius of semicircle
$r=\frac{a}{2}$
$=\frac{40}{2}$
$=20 \mathrm{~m}$
Area of semicircular plot $=\frac{1}{2} \pi r^{2}$
$=\frac{1}{2} \times 3.14 \times 20 \times 20$
$=628 \mathrm{~m}^{2}$
Now, the total area of plot is sum of area of four semicircular plots.
Total Area of plot $=4 \times$ Area of semicircle
$=4 \times 628 \mathrm{~m}^{2}$
$=2512 \mathrm{~m}^{2}$
Since, The cost of turfing the plot per square meter $=$ Rs $1.25$
So, The cost of turfing 2512 square meter plot $=$ Rs $1.25 \times 2512$
$=\operatorname{Rs} 3140 /-$