A solution containing 2.675 g

Question:

A solution containing $2.675 \mathrm{~g}$ of $\mathrm{CoCl}_{3} .6 \mathrm{NH}_{3}\left(\right.$ molar mass $=267.5 \mathrm{~g} \mathrm{~mol}^{-1}$ ) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of $\mathrm{AgNO}_{3}$ to give $4.78 \mathrm{~g}$ of $\mathrm{AgCl}$ (molar mass $=143.5 \mathrm{~g} \mathrm{~mol}^{-1}$ ). The formula of the complex is :-

  1. $\left[\mathrm{CoCl}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{Cl}_{2}$

  2. $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}$

  3. $\left[\mathrm{CoCl}_{2}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}$

  4. $\left[\mathrm{CoCl}_{3}\left(\mathrm{NH}_{3}\right)_{3}\right]$

Correct Option: , 2

Solution:

Solution not required

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