A solid metal cone with base radius of 12 cm and height 24 cm is melted to form solid spherical balls of diameter 6 cm each.

Question:

A solid metal cone with base radius of 12 cm and height 24 cm is melted to form solid spherical balls of diameter 6 cm each. Find the number of balls thus formed.

 

Solution:

Radius of the cone = 12 cm
Height of the cone = 24 cm

Volume $=\frac{1}{3} \pi \mathrm{r}^{2} \mathrm{~h}=\frac{1}{3} \pi \times 12 \times 12 \times 24=48 \times 24 \times \pi \mathrm{cm}^{3}$

Radius of each ball $=3 \mathrm{~cm}$

Volume of each ball $=\frac{4}{3} \pi \mathrm{r}^{3}=\frac{4}{3} \pi \times 3 \times 3 \times 3=36 \pi \mathrm{cm}^{3}$

 

Total number of balls formed by melting the cone $=\frac{\text { Volume of cone }}{\text { Volume of a ball }}=\frac{48 \times 24 \pi}{36 \pi}=32$

 

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