A shopkeeper sells a saree at 8% profit and a sweater at 10% discount, thereby, getting a sum ₹ 1008. If she had sold the saree at 10% profit and the
sweater at 8% discount, she would have got ₹ 1028 then find the cost of the saree and the list price (price before discount) Of the sweater.
Let the cost price of the saree and the list price of the sweater be ₹ x and ₹ y, respectively.
Case I Sells a saree at $8 \%$ profit + Sells a sweater at $10 \%$ discount $=₹ 1008$
$\Rightarrow \quad(100+8) \%$ of $x+(100-10) \%$ of $y=1008$
$\Rightarrow \quad 108 \%$ of $x+90 \%$ of $y=1008$
$\Rightarrow \quad 1.08 x+0.9 y=1008$ $\ldots$ (i)
Case II Sold the saree at $10 \%$ profit + Sold the sweater at $8 \%$ discount $=₹ 1028$
$\Rightarrow \quad(100+10) \%$ of $x+(100-8) \%$ of $y=1028$
$\Rightarrow \quad 110 \%$ of $x+92 \%$ of $y=1028$
$\Rightarrow \quad 1.1 x+0.92 y=1028$ .....(ii)
On putting the value of $y$ from Eq. (i) into Eq. (ii), we get
$1.1 x+0.92\left(\frac{1008-1.08 x}{0.9}\right)=1028$
$\Rightarrow \quad 1.1 \times 0.9 x+927.36-0.9936 x=1028 \times 0.9$
$\Rightarrow \quad 0.99 x-0.9936 x=9252-927.36$
$\Rightarrow \quad-0.0036 x=-2.16$
$\therefore$ $x=\frac{2.16}{0.0036}=600$
On putting the value of $x$ in Eq. (i), we get
$1.08 \times 600+0.9 y=1008$
$\Rightarrow \quad 108 \times 6+0.9 y=1008$
$\Rightarrow \quad 0.9 y=1008-648$
$\Rightarrow \quad 0.9 y=360$
$\Rightarrow \quad y=\frac{360}{0.9}=400$
Hence, the cost price of the saree and the list price (price before discount) of the sweater are ₹ 600 and ₹ 400, respectively.