Question:
A scooter accelerates from rest for time $t_{1}$ at constant rate $a_{1}$ and then retards at constant rate $\mathrm{a}_{2}$ for time $\mathrm{t}_{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be:
Correct Option: , 2
Solution:
(2)
From given information:
For $1^{\text {st }}$ interval
$a_{1}=\frac{v_{0}}{t_{1}}$
$v_{0}=a_{1} t_{1} \quad \ldots . .(1)$
For $2^{\text {nd }}$ interval
$a_{2}=\frac{v_{0}}{t_{2}}$
$v_{0}=a_{2} t_{2} \quad \ldots \ldots(2)$
from (1)\&(2)
$a_{1} t_{1}=a_{2} t 2$
$\frac{t_{1}}{t_{2}}=\frac{a_{2}}{a_{1}}$
