A Saturn year is $29.5$ times the earth year. How far is the Saturn from the sun if the earth is $1.50 \times 10^{8} \mathrm{~km}$ away from the sun?
Distance of the Earth from the Sun, $r_{\mathrm{e}}=1.5 \times 10^{8} \mathrm{~km}=1.5 \times 10^{11} \mathrm{~m}$'
Time period of the Earth $=T_{e}$
Time period of Saturn, $T_{S}=29.5 T_{e}$
Distance of Saturn from the Sun $=r_{\mathrm{s}}$
From Kepler's third law of planetary motion, we have
$T=\left(\frac{4 \pi^{2} r^{3}}{\mathrm{G} M}\right)^{\frac{1}{2}}$
For Saturn and Sun, we can write
$\frac{r_{s}^{3}}{r_{e}^{3}}=\frac{T_{s}^{2}}{T_{e}^{2}}$
$r_{s}=r_{e}\left(\frac{T_{s}}{T_{e}}\right)^{\frac{2}{3}}$
$=1.5 \times 10^{11}\left(\frac{29.5 T_{e}}{T_{e}}\right)^{\frac{2}{3}}$
$=1.5 \times 10^{11}(29.5)^{\frac{2}{3}}$
$=1.5 \times 10^{11} \times 9.55$
$=14.32 \times 10^{11} \mathrm{~m}$
Hence, the distance between Saturn and the Sun is $1.43 \times 10^{12} \mathrm{~m}$.