Question:
A refrigerator consumes an average $35 \mathrm{~W}$ power to operate between temperature $-10^{\circ} \mathrm{C}$ to $25^{\circ} \mathrm{C}$. If there is no loss of energy then how much average heat per second does it transfer ?
Correct Option: 1
Solution:
$\frac{T_{L}}{T_{H}-T_{L}}=$ C.O.P. $=\frac{\frac{d H}{d t}}{\frac{d W}{d t}}$
$\frac{263}{35} \times 35=\frac{\mathrm{dH}}{\mathrm{dt}}$
$\frac{\mathrm{dH}}{\mathrm{dt}}=263$ watts
Ans. 1