A rectangular diesel tanker is 2 m long, 2 m wide and 40 cm deep.

Lenght of the rectangular diesel tanker $=2 \mathrm{~m}$

Breadth $=2 \mathrm{~m}$

Height $=40 \mathrm{~cm}$

$=40 \times \frac{1}{100} \mathrm{~m} \quad(\because 1 \mathrm{~m}=100 \mathrm{~cm})$

$=0.4 \mathrm{~m}$

So, volume of the tanker $=$ lenght $\times$ breadth $\times$ height

$=2 \times 2 \times 0.4$

$=1.6 \mathrm{~m}^{3}$

We konw that $1 \mathrm{~m}^{3}=1000 \mathrm{~L}$

i.e., $1.6 \mathrm{~m}^{3}=1.6 \times 1000 \mathrm{~L}=1600 \mathrm{~L}$

$\therefore$ The tanker can hold $1600 \mathrm{~L}$ of diesel.