Question:
A reactant (A) forms two products :
$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{B}$, Activation Energy $\mathrm{Ea}_{1}$
$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{C}$, Activation Energy $\mathrm{Ea}_{2}$
If $\mathrm{Ea}_{2}=2 \mathrm{Ea}_{1}$, then $\mathrm{k}_{1}$ and $\mathrm{k}_{2}$ are related as :-
Correct Option: 1
Solution:
$\mathrm{k}_{2}=\mathrm{k}_{1}(2)^{5}=32 \mathrm{k}_{1}$