Question:
A ray of laser of a wavelength $630 \mathrm{~nm}$ is incident at an angle of $30^{\circ}$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is $2.42$ and that of air is 1 . Choose the correct option.
Correct Option: , 3
Solution:
$\sin \theta_{C}=\frac{1}{\mu}=\frac{1}{2 \mu_{2}}<\sin \theta_{C}$
$\sin \theta>\sin \theta_{C}$
$\theta>\theta_{\mathrm{C}}$
Total internal reflection will happen
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