Question:
A random variable $X$ has the following probability distribution:
$\begin{array}{lllllll}X & : & 1 & 2 & 3 & 4 & 5\end{array}$
$\mathrm{P}(\mathrm{X}) \quad: \quad \mathrm{K}^{2} \quad 2 \mathrm{~K} \quad \mathrm{~K} \quad 2 \mathrm{~K} \quad 5 \mathrm{~K}^{2}$
Then $\mathrm{P}(\mathrm{X}>2)$ is equal to :
Correct Option: , 2
Solution:
