A railway half ticket costs half the full fare and the reservation charge is the same on half ticket as on full ticket.

Let take first class full of fare is Rs $x$ and reservation charge is Rs $y$ per ticket

Then half of the ticket as on full ticket $=\frac{x}{2}$

According to the given condition we have

$x+y=216 \cdots(i)$

$x+y+\left(\frac{x}{2}\right)+y=327$

$x+\frac{x}{2}+y+y=327$

$\frac{3 x}{2}+2 y=327 \cdots(i i)$

Multiplying equation  by 2 we have

$2 x+2 y=432 \cdots(\mathrm{iii})$

Subtracting $(i i)$ from $(i i i)$ we get

$\frac{4 x-3 x}{2}=105$

$\frac{1 x}{2}=105$

$x=105 \times 2$

$x=210$

Putting $x=210$ in equation $(i)$ we get

$x+y=216$

$210+y=216$

$y=216-210$

$y=6$

Hence, the basic first class full fare is 210

The reservation charge is Rs 6 .