Question:
A prism of angle $\mathrm{A}=1^{\circ}$ has a refractive index $\mu=1.5$. A good estimate for the minimum angle of deviation (in degrees) is close to N/ 10. Value of $\mathrm{N}$ is___________.
Solution:
$\delta_{\min }=(\mu-1) \mathrm{A}$
$=(1.5-1) 1$
$=0.5$
$\delta_{\min }=\frac{5}{10}$
$\mathrm{N}=5$