Question: A point on the ellipse, $4 x^{2}+9 y^{2}=36$, where the normal is parallel to the line, $4 x-2 y-5$ $=0$, is :-
$\left(\frac{8}{5},-\frac{9}{5}\right)$
$\left(-\frac{9}{5}, \frac{8}{5}\right)$
$\left(\frac{8}{5}, \frac{9}{5}\right)$
$\left(\frac{9}{5}, \frac{8}{5}\right)$
Correct Option: , 4
Solution:
