Question:
A plane electromagnetic wave with frequency of $30 \mathrm{MHz}$ travels in free space. At particular point in space and time, electric field is $6 \mathrm{~V} / \mathrm{m}$. The magnetic field at this point will be $x \times 10^{-8} \mathrm{~T}$. The value of $x$ is
Solution:
$|\mathrm{B}|=\frac{|\mathrm{E}|}{\mathrm{C}}=\frac{6}{3 \times 10^{8}}$
$=2 \times 10^{-8} \mathrm{~T}$
$\therefore x=2$
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