Question:
A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is $\frac{1}{a} \mathrm{~s}$. The value of 'a' to the nearest integer is______
Solution:
$t=\frac{2}{12}=\frac{1}{6}$
$\therefore$ Correct answer $=6.00$
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