A particle performs simple harmonic motion

Question:

A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position

is $\frac{1}{\mathrm{a}} \mathrm{s}$. The value of 'a' to the nearest integer is___________.

 

Solution:

$t=\frac{2}{12}=\frac{1}{6}$

$\therefore$ Correct answer $=6.00$

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