Question:
A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position
is $\frac{1}{\mathrm{a}} \mathrm{s}$. The value of 'a' to the nearest integer is___________.
Solution:
$t=\frac{2}{12}=\frac{1}{6}$
$\therefore$ Correct answer $=6.00$
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