Question: A particle is moving in a circular path of radius a under the action of an attractive potential $\mathrm{U}=-\frac{\mathrm{k}}{2 \mathrm{r}^{2}}$. Its total energy is :-
$\frac{k}{2 a^{2}}$
Zero
$-\frac{3}{2} \frac{\mathrm{k}}{\mathrm{a}^{2}}$
$-\frac{\mathrm{k}}{4 \mathrm{a}^{2}}$
Correct Option: , 2
Solution:
