Question: A particle is moving with velocity $\vec{v}=K(y \hat{i}+x \hat{j})$, where $K$ is a constant. The general equation for its path is :
$\mathrm{y}^{2}=\mathrm{x}^{2}+$ constant
$y=x^{2}+$ constant
$\mathrm{y}^{2}=\mathrm{x}+\mathrm{constant}$
$x y=$ constant
Correct Option: 1
Solution:
