Question:
A parallel-plate capacitor has plate area $100 \mathrm{~cm}$-square and piate separation I.0 cm. A glass plate (dielectric constant $6.0$ ) of thickness $6.0 \mathrm{~mm}$ and an ebonite plate (dielectric constant 4.0) are inserted one over the other to fill the space between the plates of the capacitor. Find the new capacitance.
Solution:
