Question:
A modern grand-prix racing car of mass $\mathrm{m}$ is travelling on a flat track in a circular arc of radius $\mathrm{R}$ with a speed $\mathrm{v}$. If the coefficient of static friction between the tyres and the track is $\mu_{s}$, then the magnitude of negative lift $F_{L}$ acting downwards on the car is:
(Assume forces on the four tyres are identical and $g=$ acceleration due to gravity)
Correct Option: , 2
Solution:
(2)
$\mu_{s} N=\frac{m v^{2}}{R}$
$N=\frac{m v^{2}}{\mu_{s} R}=m g+F_{L}$
$F_{L}=\frac{m v^{2}}{\mu_{s} R}-m g$