Question:
A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed?
Correct Option: , 3
Solution:
From potential energy curve
$U_{\max }=\frac{1}{2} \mathrm{kA}^{2} \Rightarrow 10=\frac{1}{2} \mathrm{k}(2)^{2}$
$\Rightarrow \mathrm{k}=5$
Now $\mathrm{T}_{\text {spring }}=\mathrm{T}_{\text {pendulum }}$
$2 \pi \sqrt{\frac{5}{5}}=2 \pi \sqrt{\frac{4}{g}}$
$\Rightarrow 1=\sqrt{\frac{4}{g}} \Rightarrow g=4$ on planet
Option (3)