A machine is purchased for Rs 625000.

Initial value of the machine, $P=$ Rs 625000

Rate of depreciation, $R=8 \%$

Time, $n=2$ years

Then the value of the machine after two years is given by

Value $=P \times\left(1-\frac{R}{100}\right)^{n}$

$=$ Rs $625000 \times\left(1-\frac{8}{100}\right)^{2}$

$=$ Rs $625000 \times\left(\frac{100-8}{100}\right)^{2}$

$=$ Rs $625000 \times\left(\frac{92}{100}\right)^{2}$

$=$ Rs $625000 \times\left(\frac{23}{25}\right)^{2}$

$=$ Rs $625000 \times\left(\frac{23}{25}\right) \times\left(\frac{23}{25}\right)$

$=$ Rs $(1000 \times 23 \times 23)$

$=$ Rs 529000

Therefore, the value of the machine after two years will be Rs. 529000 .