Question:
A line passes through the point $A(-2,4,-5)$ and is parallel to the line $\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}$. The vector equation of the line is
A. $\overrightarrow{\mathrm{r}}=(-3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-8 \hat{\mathrm{k}})+\lambda(-2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-5 \hat{\mathrm{k}})$
B. $r=(-2 \hat{\imath}+4 \hat{\jmath}-5 \hat{k})+\lambda(3 \hat{\imath}+5 \hat{\jmath}+6 \hat{k})$
C.$\overrightarrow{\mathrm{r}}=(3 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}+6 \hat{\mathrm{k}})+\lambda(-2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}-5 \hat{\mathrm{k}})$
D. none of these
Solution:
