Question:
A letter of english alphabets is chosen at random. Determine the probability that the letter is a consonant
Solution:
We know that, in english alphabets, there are (5 vowels + 21 consonants)=26 letters. So,
total number of outcomes in english alphabets are,
n(S) = 26
Let $E=$ Event of choosing a english alphabet, which is a consonent
$=\{b, c, d, t, g, h, j, k, l, m, n, p, q, r, s, t, v, w, x, y, z\}$
$\therefore \quad n(E)=21$
Hence, required probability $=\frac{n(E)}{n(S)}=\frac{21}{26}$