A horse is placed for grazing inside a rectangular

It is given that a horse is tethered to one corner of a rectangular field (40 m × 36 m) by a 14 m long rope.

Let r m be the radius of a circle. Then area A of circle is

$A=\pi \mathrm{r}^{2} \mathrm{~m}^{2}$

$=\frac{22}{7} \times 14 \times 14 \mathrm{~m}^{2}$

$=616 \mathrm{~m}^{2}$

Since the horse can graze inside the rectangular field only, the required area is quadrant of circle. So,

Required area $=\frac{\mathrm{A}}{4}=\frac{616}{4}=154 \mathrm{~m}^{2}$

Hence the horse can graze 154 m2 area.