Question:
A hemispherical portion of the radius of a solid glass $(\mu=1.5)$ of radius $r$ is silvered to make the inner side reflecting. An object is placed in the axis of the hemisphere at a distance $3 \mathrm{r}$ from the center of the sphere. The light from the object is refracted of the sphere. The light from the object is refracted at the unsilvered part, and then reflected from the object is refracted from the silvered part and again refracted at the unsilvered part. Locate the final image formed.
Solution:
When refraction takes place from ACB then,
$v=-2 r$
Therefore, Image is formed at $\mathrm{E}$.