A five digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions.
A five digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is
(a) 216
(b) 600
(c) 240
(d) 3125
Five digit number is to be formed from 0,1,2,3,4 and 5.
Such that number is divisible by 3.
Any number is divisible by 3 if sum of its digits out of these digits,
1, 2, 3, 4, 5 and 0, 1, 2, 4, 5 sum up to be a multiple of 3
→ for 1,2,3,4,5,
The number of ways a five digit number which is divisible by 3 is 5 × 4 × 3 × 2 × 1 (∵ no restriction is there)
→ for 0,1, 2, 4, 5
The number of ways a five digit number which is divisible by 3 is 4 × 4 × 3 × 2 × 1 = 96 (∵ 0 cannot be placed or first place)
∴ Total number formed
= 120 + 96
= 216
Hence, the correct answer is option A.