A factory manufactures 120000 pencils daily.

Given, pencils are cylindrical in shape.

Length of one pencil = 25 cm

and circumference of base = 1.5 cm

$\Rightarrow$ $r=\frac{1.5 \times 7}{22 \times 2}=0.2386 \mathrm{~cm}$

Now curved surface area of one pencil $=2 \pi r h$

$=2 \times \frac{22}{7} \times 0.2386 \times 25$

$=\frac{262.46}{7}=37.49 \mathrm{~cm}^{2}$

$=\frac{37.49}{100} \mathrm{dm}^{2}$ $\left[\because 1 \mathrm{~cm}=\frac{1}{10} \mathrm{dm}\right]$

$=0.375 \mathrm{dm}^{2}$

$\therefore$ Curved surface area of 120000 pencils $=0.375 \times 120000=45000 \mathrm{dm}^{2}$

Now. cost of colouring $1 \mathrm{dm}^{2}$ curved surface of the pencils manufactured in one day

$=₹ 0.05$

Cost of colouring 45000 dm2 curved surface = ₹ 2250