Question:
A die is thrown. Find the probability of
getting a 2 or a 3
Solution:
We know that,
Probability of occurrence of an event
$=\frac{\text { Total no.of Desired outcomes }}{\text { Total no.of outcomes }}$
Total outcomes are $1,2,3,4,5,6$, and the desired outcomes are 2,3
Therefore, total no.of outcomes are 6 , and total no.of desired outcomes are 2
Probability of getting a 2 or 3
$=\frac{2}{6}$
$=\frac{1}{3}$
Conclusion: Probability of getting 2 or 3 when a die is thrown is $\frac{1}{3}$