A cylindrical jar of radius 6 cm contains oil. Iron spheres each of radius 1.5 cm are immersed in the oil. How many spheres are necessary to raise the level of the oil by two centimetres?
The radius of the cylindrical jar is 6cm. The volume of the oil of height 2cm contained in the jar is
$V=\pi \times(6)^{2} \times 2$ cubic $\mathrm{cm}$
The radius of each small sphere is 1.5cm. Therefore, the volume of each small sphere is
$V_{1}=\frac{4}{3} \times \pi \times(1.5)^{3}$ cubic $\mathrm{cm}$
Since, the volume of the raised water is same as the sum of the volumes of the immersed iron spheres, we have the number of immersed sphere is
$\frac{V}{V_{1}}=\frac{\pi \times(6)^{2} \times 2}{\frac{4}{3} \times \pi \times(1.5)^{3}}$
$=\frac{3 \times 36 \times 2 \times 1000}{4 \times 15 \times 15 \times 15}$
$=16$
Therefore, the number of iron spheres is 16