A cylindrical container is filled with ice-cream,

Solution:

Volume of cylindrical container

$=\pi r^{2} h$

$=\pi \times(6)^{2} \times 15$

Amount of ice-cream distributed to 10 children $=\frac{\pi \times(6)^{2} \times 15}{10}$

Therefore,

Height of conical portion = 2 × diameter of its bars

Let the diameter of bare = r

Height = 2r

Therefore,

Volume of the cones

$=\frac{1}{3} \pi\left(\frac{r}{2}\right)^{2} h+\frac{2}{3} \pi r^{3}$

$=\frac{1}{3} \pi\left(\frac{r}{2}\right)^{2}(h+2 r)$

$r=\frac{\pi r^{3}}{4}$

Therefore,

Volume of the cones = amount distributed

$r=\sqrt[3]{6 \times 6 \times 6}=6 \mathrm{~cm}$