Question:
A cuboidal block of silver is 9 cm long, 4 cm broad and 3.5 cm in height. From it, beads of volume 1.5 cm3 each are to be made. Find the number of beads that can be made from the block.
Solution:
Length of the cuboidal block of silver $=9 \mathrm{~cm}$
Breadth $=4 \mathrm{~cm}$
Height $=3.5 \mathrm{~cm}$
Now, volume of the cuboidal block $=$ length $\times$ breadth $\times$ height
$=9 \times 4 \times 3.5$
$=126 \mathrm{~cm}^{3}$
$\therefore$ The required number of beads of volume $1.5 \mathrm{~cm}^{3}$ that can be made from the block $=\frac{\text { volume of the silver block }}{\text { volume of one bead }}$
$=\frac{126 \mathrm{~cm}^{3}}{1.5 \mathrm{~cm}^{3}}$
$=84$