Question:
A cube of 9 cm edge is immersed completely in a rectangular vessel containing water. If the dimensions of the base are 15 cm and 12 cm, find the rise in water level in the vessel.
Solution:
Volume of the cube $=\mathrm{s}^{3}=9^{3}=729 \mathrm{~cm}^{3}$
Area of the base $=\mathrm{l}^{*} \mathrm{~b}=15^{*} 12=180 \mathrm{~cm}^{2}$
Rise in water level $=\frac{\text { Volume of the cube }}{\text { Area of base of rectangular vessel }}$
= 729/180
= 4.05 cm