Question:
A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in
(i) Sixes
(ii) fours
(iii) twos
(iv) singles
Solution:
(i) The cricketer hits 3 sixes.
i.e., $3 \times 6=18$
$\therefore \frac{18}{62} \times 100=29.03 \%$
(ii) The cricketer hits 8 fours.
i. e., $8 \times 4=32$
$\therefore \frac{32}{62} \times 100=51.61 \%$
(iii) The cricketer hits 2 twos.
i. e., $2 \times 2=4$
$\therefore \frac{4}{62} \times 100=6.45 \%$
(iv) The cricketer hits 8 singles.
i. e., $8 \times 1=8$
$\therefore \frac{8}{62} \times 100=12.90 \%$