Question:
A coin is tossed 1000 times with the following sequence: Head: 455, Tail = 545. Compute the probability of each event
Solution:
It is given that the coin is tossed 1000 times. The number of trials is 1000
Let us denote the event of getting head and of getting tails be E and F respectively. Then
Number of trials in which the E happens = 455
So,
Probability of $\mathrm{E}=\frac{\text { Number of even theads }}{\text { Total no of trials }}$
i.e. $P(E)=\frac{455}{1000}=0.455$
Similarity, the probability of the event getting a tail $=\frac{\text { Number of tails }}{\text { Total no of trials }}$
i.e. $P(F)=\frac{545}{1000}=0.545$