Question:
A child has die whose 6 faces show the letters given below.
The die is thrown once. What is the probability of getting (i) A, (ii) B?
Solution:
When the die is thrown once, then any one of the six faces can show up.
∴ Total number of outcomes = 6
(i) There are 3 faces on the die showing the letter A.
$\therefore \mathrm{P}($ Getting the letter $\mathrm{A})=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{3}{6}=\frac{1}{2}$
(ii) There are 2 faces on the die showing the letter B.
Favourable number of outcomes = 2
$\therefore \mathrm{P}($ Getting the letter $\mathrm{B})=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{2}{6}=\frac{1}{3}$
Favourable number of outcomes = 3